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# Basic Chemistry Conversion

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• ### Basic Chemistry Conversion

Xaxikata > 01-19-2020, 03:48 AM

I believe I understand conversion somewhat, but I feel like a couple parts of the concept are sketchyRead my book, my teacher\'s notes, another teacher\'s lecture, and the quot;Idiot\'s Guide to.quot; but haven\'t found enough examples to pick it up.If someone could walk through this problem for me, I\'d be forever grateful! It covers all basic steps I thinkDo I need to convert the percentages? If I can get all the information to the density equation, I\'m home free.A ruby contains 52.7% aluminum and 47.1% oxygen with traces of chromiumIf the ruby was found to contain 0.125g of aluminum, what is the mass of the ruby?Also, if you know a good website, I\'d appreciate! I can\'t find any that give examples.Remember, that percent means parts per hundred, so you would have 52.7g of Al; 47.1g of Oxygen; and .2g of ChromiumThis would make your ruby 100gTo do your conversion start with what you have, which is .125g of Aland you know that for every 100g ruby you have 52.7g of Aluminum Heres how I would set up the problem: .125g Al x 100g Ruby/52.7g Al (The Al would cancel out leaving you with the mass of the ruby in grams.) I got that the ruby should weigh .237g If you used your answer of .237g to find out how many grams of Oxygen were in a ruby of that mass, it would look like this (remember we know how much oxygen is a ruby of 100g, so we can use that as a conversion factor): .237g Ruby x 47.1 g Oxygen/100g Ruby .112g Oxygen If you add this with the amount of Al, you get the mass of the ruby- .125g Al + .112 g O .237 As far as the unit conversions go, just remember that The units you want to finish with need to be on top Hope that helps!Other related question