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01-13-2020, 09:26 AM
Aluminum metal reacts with hydrochloric acid, HCl, to form hydrogen gas (H2) and a solution of aluminum chloride. Write and balance the equation. Can someone help I just dont get this Al2 + 6HCl → 3H2 + 2AlCl3 Al2 + 2HCl → H2 + 2AlCl 2Al + 6HCl → 3H2 + 2AlCl3 Al + 2HCl → H2 + AlCl2 6Al + 2HCl → H2 + 2Al3ClAluminum reacts with HCl ... This is a single replacement reaction in which aluminum replaces hydrogen ion. Aluminum metal is oxidized by H+, and H+ is reduced by aluminum metal. Chloride ion is a spectator ion. You also need to know that aluminum usually exhibits a +3 oxidation state. This means that there will be three chloride ions (oxidation number of -1) for each aluminum. 2Al(s) + 6HCl(aq) -- 2AlCl3(aq) + 3H2(g)This Site Might Help You. RE: Help balancing chemistry equation Aluminum metal reacts with hydrochloric acid, HCl, to form hydrogen gas? Aluminum metal reacts with hydrochloric acid, HCl, to form hydrogen gas (H2) and a solution of aluminum chloride. Write and balance the equation. Can someone help I just dont get this Al2 + 6HCl → 3H2 + 2AlCl3 Al2 + 2HCl → H2 + 2AlCl 2Al + 6HCl → 3H2 + 2AlCl3 Al + 2HCl → H2 + AlCl2...Aluminum And Hydrochloric Acidthis is an oxidation reduction reaction it has to be belanced has one so first you need to calculate the oxidation numbers (o.n.) of the species: eq: Al(s) + HCl → H2 (g) + AlCl3 o.n.: 0......+1 -1 ......0......... +3 -1 The oxidation number of H changes of +1 to 0 so its a reduction reaction. The oxidation number of Al changes of 0 to +3 so its a oxidation reaction. calculate the balanced equation (Al(s) → AlCl3 + 3e-) x 2 (2e- + 2HCl → H2) x 3 --------------------------------------... 2Al(s) + 6HCl → + 2AlCl3 + 3 H22NH4Cl+Ca(OH)2-CaCl+2NH3+2H2O 18 Zn+2Cl-ZnCl2+H2 19 F2+2NaCl-2NaF+Cl2 20 CaO+SO2-CaSO3 21 2CaSO3+O2-2CaSO4 22 2HgO-2Hg+O2 23 CH3OH-CO+2H2 24 2KNO3-2KNO2+O2 you put the question in wrong section. Answer the others by yourself. I have given lots of examples there.Other related question